(x+3)(2x+7)-(x+3)^2=0

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Solution for (x+3)(2x+7)-(x+3)^2=0 equation: 



(x+3)(2x+7)-(x+3)^2=0

We multiply parentheses ..

(+2x^2+7x+6x+21)-(x+3)^2=0

We get rid of parentheses

2x^2+7x+6x-(x+3)^2+21=0

We add all the numbers together, and all the variables

2x^2+13x-(x+3)^2+21=0

We move all terms containing x to the left, all other terms to the right

2x^2+13x-(x+3)^2=-21

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